Determine the correct order of stability for | vedclass

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Question

(C) The stability of carbocations is determined by the electronic effects of the substituents attached to the benzene ring. $(a)$ The tert-butyl group

Vedclass · Accepted Answer

$c > d > a > b$

Vedclass · Answer

(C) The stability of carbocations is determined by the electronic effects of the substituents attached to the benzene ring. $(a)$ The tert-butyl group shows a $+I$ effect,which stabilizes the carbocation. $(b)$ The $-NO_2$ group shows a $-M$ effect,which strongly destabilizes the carbocation. $(c)$ The $-O-CO-CH_3$ group shows a $+M$ effect (due to the lone pair on oxygen),which significantly stabilizes the carbocation. $(d)$ The $-CH_3$ group shows a $+H$ (hyperconjugation) effect,which stabilizes the carbocation. Comparing the effects: $+M > +H > +I > -M$. Therefore,the order of stability is $c > d > a > b$.

Determine the correct order of stability for the following carbocations:

Similar Questions

The correct order of stability for the following alkoxides is:
$(A)$ $CH_3CH(NO_2)O^-$
$(B)$ $CH_2=C(NO_2)O^-$
$(C)$ $O_2N-CH=CH-O^-$

Which of the following is the most stable carbanion?

Which of the following does not show hyperconjugation?

The decreasing order of stability of the following anions is:
$(P)$ $p-OCH_3-C_6H_4-CH_2^-$
$(Q)$ $p-CHO-C_6H_4-CH_2^-$
$(R)$ $p-Cl-C_6H_4-CH_2^-$
$(S)$ $p-CH_3-C_6H_4-CH_2^-$

Given below are two statements:
Statement $I:$ Hyperconjugation is a permanent effect.
Statement $II:$ Hyperconjugation in ethyl cation $(CH_{3}CH_{2}^{+})$ involves the overlapping of $C_{sp^{3}}-H_{1s}$ bond with the empty $2p$ orbital of the adjacent carbon.
Choose the correct option:

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